When chlorine (as a gas or dissolved in water) is added to sodium bromide solution, the chlorine takes the place of the bromine. Because chlorine is more reactive than bromine, it displaces bromine from sodium bromide.
The solution turns brown. This brown colour is the displaced bromine. The chlorine has gone to form sodium chloride.
In this equation, the Cl and Br have swapped places:
chlorine + sodium bromide → sodium chloride + bromine
Cl2(aq) + 2NaBr(aq) → 2NaCl(aq) + Br2(aq)
This type of reaction happens with all the halogens. A more reactive halogen displaces a less reactive halogen from a solution of one of its salts.
If you test different combinations of the halogens and their salts, you can work out a reactivity series for Group 7:
It doesn’t matter whether you use sodium salts or potassium salts – it works the same for both types.
The slideshow shows what happens when chlorine, bromine and iodine are added to various halogen salts:
Adding chlorine, bromine and iodine to halogen salts
Redox reactions involve both oxidation (loss of electrons) and reduction (gain of electrons). You could remember it as: OIL RIG – Oxidation Is Loss of electrons, Reduction Is Gain of electrons.
Halogen displacement reactions are redox reactions because the halogens gain electrons and the halide ions lose electrons.
When we consider one of the displacement reactions, we can see which element is being oxidised and which is being reduced.
bromine + potassium iodide → iodine + potassium bromide
Br2 + 2KI → I2 + 2KBr
As an ionic equation (ignoring the ‘spectator’ potassium ions):
Br2 + 2I- → I2 + 2Br-
We can see that the bromine has gained electrons, so it has been reduced. The iodide ions have lost electrons, so they have been oxidised.