India will stage its first world ranking snooker tournament in October.
The Indian Open in Delhi will feature 64 of the world's top players and will offer prize money of £300,000, with £50,000 going to the winner.
World Snooker chairman Barry Hearn said: "This is a momentous announcement for snooker as we stage a world ranking event in India for the very first time.
- China (5)
- Wuxi Classic, Shanghai Masters, International Championship, Haikou World Open, China Open
- England (2)
- UK Championship, World Championship
- Australia (1)
- Australian Open
- India (1)
- Indian Open
- Germany (1)
- German Masters
- Wales (1)
- Welsh Open
- Ireland (1)
- Players Tour Championship
"If we can replicate the phenomenal
success we have had in China
then India will be a very exciting prospect."
The World Professional Billiards and Snooker Association chairman Jason Ferguson added: "I have been in Delhi to finalise the agreement and have witnessed first-hand the enthusiasm for snooker in India.
"We now have two Indian players on the professional tour; Aditya Mehta who reached the last 16 of the International Championship last season and Pankaj Advani who got to the semi-finals of the Paul Hunter Classic and the
quarter-finals of the Welsh Open.
"The people in India really love our game and I've no doubt this event will be a great success and provide a basis for snooker's growth there."
A qualifying round will be held at at the Doncaster Dome in August with players needing to win one match to earn a place at the tournament in India, which will be held from 14 to 18 October.