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Physics

The Gas Laws

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Pressure and volume of a gas (Boyle's Law)

Imagine a gas is trapped in a cylinder by a piston.

If the piston is pushed in, the gas particles will have less room to move as the volume the gas occupies has been decreased.

Process of equilibrium

Piston prior to being pushed in

Piston in relaxed position prior to being pushed in

Because there has been a decrease in volume the particles will collide more frequently with the walls of the container. Each time they collide with the walls, they exert a force on them. More collisions mean more force, so the pressure will increase.

When the volume decreases the pressure increases. This shows that the pressure of a gas is inversely proportional to its volume.

From this we can derive the equation:

p_1 V_1  = p_2 V_2

Where:

  • p_1is the starting pressure
  • V_1is the starting volume
  • p_2is the finishing pressure
  • V_2is the finishing volume
Question

A sealed syringe contains 10 10-6 m3 of air at 1 × 105 Pa. The plunger is pushed until the volume of trapped air is 4 10-6 m3. If there is no change in temperature what is the new pressure of the gas?

toggle answer

Answer

p_1= 1 × 105 Pa

V_1= 10 × 10-6 m3

V_2= 4 × 10-6 m3

 

p_1 V_1  = p_2 V_2

Therefore,

p_2  = {{p_1 V_1 } \over {V_2 }}

p_2  = {{1 \times 10^5  \times 10 \times 10^{ - 6} } \over {4 \times 10^{ - 6} }}

p_2 = 2.5 × 105 Pa

The new pressure in the syringe is 2.5 × 105 Pa

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