29 June 2012
Last updated at 11:49 ET
Turkey and Syria have offered very different explanations of how a Turkish F-4 Phantom jet was downed in the Mediterranean.
Syria insists the aircraft was flying low and fast, close to the Syrian coast, when they fired at it on 22 June. It was hit by land-based anti-aircraft guns with a maximum range of 2.5km (1.3 nautical miles), officials say.
Meanwhile, the Turkish authorities say that although the plane mistakenly entered Syrian airspace, it was not there when it was shot at. It was hit by a heat-seeking or laser-guided missile, they add.
According to international law, a country's airspace extends 22.2km (12 nautical miles) from its coastline, corresponding with its territorial waters.
The two accounts
|
Syrian version
|
Turkish version
|
- 11:40 local time (08:40 GMT): F-4 spotted flying at altitude of 100m (330ft), 1-2km (0.5-1 nautical miles) from Syrian coast
- Surprise meant no time to give warning
- Air defences engaged aircraft about 1km (0.5 nautical miles) from coast; it crashed into sea 10km (5 nautical miles) west of village of Om al-Tuyour
- Tail wreckage shows jet was hit by anti-aircraft gun, which has a maximum range of 2.5km (1.3 nautical miles)
|
- Approx 10:28 local time (07:28 GMT): F-4 leaves Erhac airbase in Malatya province and flies south-west over Hatay province
- 11:42: jet mistakenly enters Syrian airspace near Latakia at altitude of 61m (200ft) at speed of 300 knots
- 11:47: leaves after Turkish radar operator warning - no Syrian warning
- 11:56: jet hit 24 km (13 nautical miles) from Syrian coast at altitude of 7,400ft (2.2km) by heat-seeking or laser-guided missile.
- 11:58 crashes into the sea
|