### Calculating quantity of electricity using quantitative electrolysis

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Messages: 1 - 6 of 6
• #### Message 1.

Posted by U15264944 (U15264944) on Saturday, 25th May 2013

In the two example questions on the bitesize page about this, they don't seem to take into account the facts that the first one is per minute and the second one is in an hour. I presume this is because the numbers in question are just 1 so it wouldn't change anything? If it was in 2 hours, would you just multiply your final answer by 2? Thank you!

• #### Message 2

, in reply to message 1.

Posted by MissChemTeacher_Bitesize (U15172316) on Saturday, 25th May 2013

Hey! Not sure which questions you are talking about from the Bitesize page. If you let me know which section you're working on I'll have a look and try to help you out.

Cheers

Miss_Chem

• #### Message 3

, in reply to message 2.

Posted by U15264944 (U15264944) on Sunday, 26th May 2013

Sorry! It's in Unit 3 calculations - electrolysis - page 2 and it's the 2 example questions on that page. Thanks!

• #### Message 4

, in reply to message 3.

Posted by MissChemTeacher_Bitesize (U15172316) on Monday, 27th May 2013

Hey There!

The time in these questions doesn't play a role in any calculating as you can work these answers out using proportion.

If you're given a value for amps and time you'd need to use that to calculate the quantity of electricity, but not here. Remember in these calculations, if you're using time, that you need to convert it into seconds.

Hope that makes sense.

Cheers Miss_Chem

• #### Message 5

, in reply to message 4.

Posted by U15264944 (U15264944) on Monday, 27th May 2013

Ok, thanks! So you never have to take time into account when calculating the quantity of electricity?

• #### Message 6

, in reply to message 5.

Posted by MissChemTeacher_Bitesize (U15172316) on Tuesday, 28th May 2013

If you're using the formula: Q = I x t
You need to take time into consideration when calculating the Quantity of electricity (Q).

In the examples on the bitesize page you could do the calculation without using that formula so the time taken wasn't needed.

Hope this helps

Miss_Chem

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