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Posted by U15228749 (U15228749) on Saturday, 18th May 2013
Hydrochloric acid reacts with magnesium
according to the following equation.
Mg(s) + 2H+ (aq) --> mg2+ (aq) + H2(g)
What ~olume of 4 moll-' hydrochloric acid
reacts with 0.1 m01 of magnesium?
how would i do this one please
Posted by MissChemTeacher_Bitesize (U15172316) on Tuesday, 21st May 2013
Thanks for your Question:
Hydrochloric acid reacts with magnesium according to the following equation.
Mg(s) + 2H+ (aq) --> Mg++ (aq) + H₂(g)
What ~volume of 4 mol l¯ hydrochloric acid reacts with 0.1 moles of magnesium?
The question tells us we have 0.1 moles of magnesium so we can plug that into our mole ratio from our balanced equation.
Balanced Eq: Mg(s) : 2H+
From Q:……..0.1 :….…0.2
Using the ratio we know that we now have 0.2 moles of hydrochloric acid (2H+)
Volume of hydrochloric acid = number of moles / concentration
Volume of hydrochloric acid = 0.2 mol / 4.0 mol l¯
Volume of hydrochloric acid = 0.05l or 50cm
Hope you get the hang of this.