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Posted by MissChemTeacher_Bitesize (U15172316) on Thursday, 13th December 2012
I started my Higher class with an Avogadro calculation today.
Calculate the number of i) molecules ii) atoms in 88g of carbon dioxide, CO2.
If you need help drop me a post.
Posted by MissChemTeacher_Bitesize (U15172316) on Monday, 17th December 2012
Here is a solution to the Avogadro Problems:
(i) 1 mole of CO₂ (44g) = Avogadro constant of molecules 6.02 x 10²³
As we have 88g of CO2 we have 2 moles of CO2 = 2 x Avogadro constant.
88g of CO2 = 1.204 x 10²⁴ molecules of carbon dioxide.
(ii) As each molecule of carbon dioxide has 3 atoms per molecule we need to times the number of molecules by 3 to calculate the number of atoms.
1.204 x 10²⁴ x 3 = 3.612 x 10²⁴ atoms.
If you need help with any more Avogadro questions drop me a message on the board.
Posted by Hiza (U14875141) on Tuesday, 8th January 2013
Hi, I was wondering if you could drop in titration calculations, I think I may need practice in those.
Posted by MissChemTeacher_Bitesize (U15172316) on Thursday, 10th January 2013
No worries, I'll post some titration questions for you to try
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