This discussion has been closed.
Posted by MissChemTeacher_Bitesize (U15172316) on Sunday, 2nd December 2012
Here is a problem from the 2012 past paper.
Which of the following pairs of gases occupy the same volume?
(Assume all measurements are made under the same conditions of temperature and pressure.)
A 2 g hydrogen and 14 g nitrogen
B 32 g methane and 88 g carbon dioxide
C 7 g carbon monoxide and 16 g oxygen
D 10 g hydrogen chloride and 10 g sulphur dioxide
Post your answers below.
I'll put a solution on the board in a few days.
Posted by MissChemTeacher_Bitesize (U15172316) on Thursday, 6th December 2012
To work this out, you should know that one mole of any gas occupies the same volume.
We can use number of moles = mass / gfm
This will tell us how many moles of each gas we have, so any combinations where the number of moles are the same will occupy the same volume.
Remember that oxygen, hydrogen and nitrogen are diatomic.
A 2g of H₂ = 1 mole and 14g of N₂ = 0.5 moles
B 32g of CH₄ = 2 moles and 88g of CO₂ = 2 moles
C 7g of CO = 0.25 moles and 16g of O₂ = 0.5 moles
D 10g of HCl = 0.27 moles and 10g of SO₂ = 0.15 moles
The answer here must be B. As each combination has the same number of moles of gas, they will occupy the same volume.
If you have any questions about this or the working involved get in touch.
Copyright © 2015 BBC. The BBC is not responsible for the content of external sites. Read more.
This page is best viewed in an up-to-date web browser with style sheets (CSS) enabled. While you will be able to view the content of this page in your current browser, you will not be able to get the full visual experience. Please consider upgrading your browser software or enabling style sheets (CSS) if you are able to do so.