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Posted by Eleanor (U15451348) on Monday, 8th October 2012
I have a trig equation question that i'm really stuck on. Help would be much appreciated.
The depth of water, D metres, in a harbour is given by the formula:
D= 3 +1.75sin30h°
where h is the number of hours after midnight.
a) Calculate the maximum difference in depth of the water in the harbour.
Many thanks in advance!!!
Posted by Maths Teacher BBC (U15178780) on Wednesday, 31st October 2012
Sin30h has a maximum at 1 (from graph)
Sin30h has a minimum at -1 (from graph)
Max = 3 + 1.75 x 1 = 4.75
Min = 3 + 1.75 x -1 = 1.25
Difference between them 4.75 - 1.25 = 3.5m
Hope this helps!
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